Solve y-A/B=C

$$\frac { y - A } { B } = C$$

Solve for A

$$A=y-BC$$

$$B\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by B.

$$y-A=CB$$

Subtract y from both sides.

$$-A=CB-y$$

The equation is in standard form.

$$-A=BC-y$$

Divide both sides by -1.

$$\frac{-A}{-1}=\frac{BC-y}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$A=\frac{BC-y}{-1}$$

Divide CB-y by -1.

$$A=y-BC$$

Solve for B

$$\left\{\begin{matrix}B=\frac{y-A}{C}\text{, }&y\neq A\text{ and }C\neq 0\\B\neq 0\text{, }&C=0\text{ and }y=A\end{matrix}\right.$$

Steps for Solving Linear Equation

Variable B cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by B.

$$y-A=CB$$

Swap sides so that all variable terms are on the left hand side.

$$CB=y-A$$

Divide both sides by C.

$$\frac{CB}{C}=\frac{y-A}{C}$$

Dividing by C undoes the multiplication by C.

$$B=\frac{y-A}{C}$$

Variable B cannot be equal to 0.

$$B=\frac{y-A}{C}\text{, }B\neq 0$$