Solve y-4000/3700-4000=x-48/120-48

$$\frac { y - 4000 } { 3700 - 4000 } = \frac { x - 48 } { 120 - 48 }$$

Solve for x

$$x=-\frac{6y}{25}+1008$$

Steps for Solving Linear Equation

Subtract 4000 from 3700 to get -300.

$$\frac{y-4000}{-300}=\frac{x-48}{120-48}$$

Multiply both numerator and denominator by -1.

$$\frac{-y+4000}{300}=\frac{x-48}{120-48}$$

Subtract 48 from 120 to get 72.

$$\frac{-y+4000}{300}=\frac{x-48}{72}$$

Divide each term of -y+4000 by 300 to get -\frac{1}{300}y+\frac{40}{3}.

$$-\frac{1}{300}y+\frac{40}{3}=\frac{x-48}{72}$$

Divide each term of x-48 by 72 to get \frac{1}{72}x-\frac{2}{3}.

$$-\frac{1}{300}y+\frac{40}{3}=\frac{1}{72}x-\frac{2}{3}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{72}x-\frac{2}{3}=-\frac{1}{300}y+\frac{40}{3}$$

Add \frac{2}{3} to both sides.

$$\frac{1}{72}x=-\frac{1}{300}y+\frac{40}{3}+\frac{2}{3}$$

Add \frac{40}{3} and \frac{2}{3} to get 14.

$$\frac{1}{72}x=-\frac{1}{300}y+14$$

The equation is in standard form.

$$\frac{1}{72}x=-\frac{y}{300}+14$$

Multiply both sides by 72.

$$\frac{\frac{1}{72}x}{\frac{1}{72}}=\frac{-\frac{y}{300}+14}{\frac{1}{72}}$$

Dividing by \frac{1}{72} undoes the multiplication by \frac{1}{72}.

$$x=\frac{-\frac{y}{300}+14}{\frac{1}{72}}$$

Divide -\frac{y}{300}+14 by \frac{1}{72} by multiplying -\frac{y}{300}+14 by the reciprocal of \frac{1}{72}.

$$x=-\frac{6y}{25}+1008$$

Solve for y

$$y=-\frac{25x}{6}+4200$$

Steps for Solving Linear Equation

Subtract 4000 from 3700 to get -300.

$$\frac{y-4000}{-300}=\frac{x-48}{120-48}$$

Multiply both numerator and denominator by -1.

$$\frac{-y+4000}{300}=\frac{x-48}{120-48}$$

Subtract 48 from 120 to get 72.

$$\frac{-y+4000}{300}=\frac{x-48}{72}$$

Divide each term of -y+4000 by 300 to get -\frac{1}{300}y+\frac{40}{3}.

$$-\frac{1}{300}y+\frac{40}{3}=\frac{x-48}{72}$$

Divide each term of x-48 by 72 to get \frac{1}{72}x-\frac{2}{3}.

$$-\frac{1}{300}y+\frac{40}{3}=\frac{1}{72}x-\frac{2}{3}$$

Subtract \frac{40}{3} from both sides.

$$-\frac{1}{300}y=\frac{1}{72}x-\frac{2}{3}-\frac{40}{3}$$

Subtract \frac{40}{3} from -\frac{2}{3} to get -14.

$$-\frac{1}{300}y=\frac{1}{72}x-14$$

The equation is in standard form.

$$-\frac{1}{300}y=\frac{x}{72}-14$$

Multiply both sides by -300.

$$\frac{-\frac{1}{300}y}{-\frac{1}{300}}=\frac{\frac{x}{72}-14}{-\frac{1}{300}}$$

Dividing by -\frac{1}{300} undoes the multiplication by -\frac{1}{300}.

$$y=\frac{\frac{x}{72}-14}{-\frac{1}{300}}$$

Divide \frac{x}{72}-14 by -\frac{1}{300} by multiplying \frac{x}{72}-14 by the reciprocal of -\frac{1}{300}.

$$y=-\frac{25x}{6}+4200$$