Solve for y
y=4
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\left(y-7\right)\left(y-3\right)=\left(y-5\right)\left(y-1\right)
Variable y cannot be equal to any of the values 5,7 since division by zero is not defined. Multiply both sides of the equation by \left(y-7\right)\left(y-5\right), the least common multiple of y-5,y-7.
y^{2}-10y+21=\left(y-5\right)\left(y-1\right)
Use the distributive property to multiply y-7 by y-3 and combine like terms.
y^{2}-10y+21=y^{2}-6y+5
Use the distributive property to multiply y-5 by y-1 and combine like terms.
y^{2}-10y+21-y^{2}=-6y+5
Subtract y^{2} from both sides.
-10y+21=-6y+5
Combine y^{2} and -y^{2} to get 0.
-10y+21+6y=5
Add 6y to both sides.
-4y+21=5
Combine -10y and 6y to get -4y.
-4y=5-21
Subtract 21 from both sides.
-4y=-16
Subtract 21 from 5 to get -16.
y=\frac{-16}{-4}
Divide both sides by -4.
y=4
Divide -16 by -4 to get 4.
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