Solve y-3/5-3=x-1/2-1=

$$\frac { y - 3 } { 5 - 3 } = \frac { x - 1 } { 2 - 1 } =$$

Solve for x

$$x=\frac{y-1}{2}$$

Solution Steps

Subtract 3 from 5 to get 2.

$$\frac{y-3}{2}=\frac{x-1}{2-1}$$

Subtract 1 from 2 to get 1.

$$\frac{y-3}{2}=\frac{x-1}{1}$$

Anything divided by one gives itself.

$$\frac{y-3}{2}=x-1$$

Divide each term of y-3 by 2 to get \frac{1}{2}y-\frac{3}{2}.

$$\frac{1}{2}y-\frac{3}{2}=x-1$$

Swap sides so that all variable terms are on the left hand side.

$$x-1=\frac{1}{2}y-\frac{3}{2}$$

Add 1 to both sides.

$$x=\frac{1}{2}y-\frac{3}{2}+1$$

Add -\frac{3}{2} and 1 to get -\frac{1}{2}.

$$x=\frac{1}{2}y-\frac{1}{2}$$

Solve for y

$$y=2x+1$$

Steps for Solving Linear Equation

Subtract 3 from 5 to get 2.

$$\frac{y-3}{2}=\frac{x-1}{2-1}$$

Subtract 1 from 2 to get 1.

$$\frac{y-3}{2}=\frac{x-1}{1}$$

Anything divided by one gives itself.

$$\frac{y-3}{2}=x-1$$

Divide each term of y-3 by 2 to get \frac{1}{2}y-\frac{3}{2}.

$$\frac{1}{2}y-\frac{3}{2}=x-1$$

Add \frac{3}{2} to both sides.

$$\frac{1}{2}y=x-1+\frac{3}{2}$$

Add -1 and \frac{3}{2} to get \frac{1}{2}.

$$\frac{1}{2}y=x+\frac{1}{2}$$

Multiply both sides by 2.

$$\frac{\frac{1}{2}y}{\frac{1}{2}}=\frac{x+\frac{1}{2}}{\frac{1}{2}}$$

Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.

$$y=\frac{x+\frac{1}{2}}{\frac{1}{2}}$$

Divide x+\frac{1}{2} by \frac{1}{2} by multiplying x+\frac{1}{2} by the reciprocal of \frac{1}{2}.

$$y=2x+1$$