Solve for x
x=y-1
Solve for y
y=x+1
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\frac{y-0}{4}=\frac{x-\left(-1\right)}{3-\left(-1\right)}
Subtract 0 from 4 to get 4.
\frac{y-0}{4}=\frac{x+1}{3-\left(-1\right)}
The opposite of -1 is 1.
\frac{y-0}{4}=\frac{x+1}{3+1}
The opposite of -1 is 1.
\frac{y-0}{4}=\frac{x+1}{4}
Add 3 and 1 to get 4.
\frac{1}{4}y-0=\frac{x+1}{4}
Divide each term of y-0 by 4 to get \frac{1}{4}y-0.
\frac{1}{4}y-0=\frac{1}{4}x+\frac{1}{4}
Divide each term of x+1 by 4 to get \frac{1}{4}x+\frac{1}{4}.
\frac{1}{4}x+\frac{1}{4}=\frac{1}{4}y-0
Swap sides so that all variable terms are on the left hand side.
\frac{1}{4}x=\frac{1}{4}y-0-\frac{1}{4}
Subtract \frac{1}{4} from both sides.
\frac{1}{4}x=\frac{1}{4}y-\frac{1}{4}
Reorder the terms.
\frac{1}{4}x=\frac{y-1}{4}
The equation is in standard form.
\frac{\frac{1}{4}x}{\frac{1}{4}}=\frac{y-1}{\frac{1}{4}\times 4}
Multiply both sides by 4.
x=\frac{y-1}{\frac{1}{4}\times 4}
Dividing by \frac{1}{4} undoes the multiplication by \frac{1}{4}.
x=y-1
Divide \frac{-1+y}{4} by \frac{1}{4} by multiplying \frac{-1+y}{4} by the reciprocal of \frac{1}{4}.
\frac{y-0}{4}=\frac{x-\left(-1\right)}{3-\left(-1\right)}
Subtract 0 from 4 to get 4.
\frac{y-0}{4}=\frac{x+1}{3-\left(-1\right)}
The opposite of -1 is 1.
\frac{y-0}{4}=\frac{x+1}{3+1}
The opposite of -1 is 1.
\frac{y-0}{4}=\frac{x+1}{4}
Add 3 and 1 to get 4.
\frac{1}{4}y-0=\frac{x+1}{4}
Divide each term of y-0 by 4 to get \frac{1}{4}y-0.
\frac{1}{4}y-0=\frac{1}{4}x+\frac{1}{4}
Divide each term of x+1 by 4 to get \frac{1}{4}x+\frac{1}{4}.
\frac{1}{4}y=\frac{1}{4}x+\frac{1}{4}+0
Add 0 to both sides.
\frac{1}{4}y=\frac{1}{4}x+\frac{1}{4}
Add \frac{1}{4} and 0 to get \frac{1}{4}.
\frac{1}{4}y=\frac{x+1}{4}
The equation is in standard form.
\frac{\frac{1}{4}y}{\frac{1}{4}}=\frac{x+1}{\frac{1}{4}\times 4}
Multiply both sides by 4.
y=\frac{x+1}{\frac{1}{4}\times 4}
Dividing by \frac{1}{4} undoes the multiplication by \frac{1}{4}.
y=x+1
Divide \frac{1+x}{4} by \frac{1}{4} by multiplying \frac{1+x}{4} by the reciprocal of \frac{1}{4}.
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