Solve y-0/-3-0=x-7/-1-7

$$\frac { y - 0 } { - 3 - 0 } = \frac { x - 7 } { - 1 - 7 }$$

Solve for x

$$x=\frac{8y}{3}+7$$

Steps for Solving Linear Equation

Subtract 0 from -3 to get -3.

$$\frac{y-0}{-3}=\frac{x-7}{-1-7}$$

Subtract 7 from -1 to get -8.

$$\frac{y-0}{-3}=\frac{x-7}{-8}$$

Multiply both numerator and denominator by -1.

$$\frac{y-0}{-3}=\frac{-x+7}{8}$$

Divide each term of y-0 by -3 to get -\frac{1}{3}y-0.

$$-\frac{1}{3}y-0=\frac{-x+7}{8}$$

Divide each term of -x+7 by 8 to get -\frac{1}{8}x+\frac{7}{8}.

$$-\frac{1}{3}y-0=-\frac{1}{8}x+\frac{7}{8}$$

Swap sides so that all variable terms are on the left hand side.

$$-\frac{1}{8}x+\frac{7}{8}=-\frac{1}{3}y-0$$

Subtract \frac{7}{8} from both sides.

$$-\frac{1}{8}x=-\frac{1}{3}y-0-\frac{7}{8}$$

Reorder the terms.

$$-\frac{1}{8}x=-\frac{1}{3}y-\frac{7}{8}$$

The equation is in standard form.

$$-\frac{1}{8}x=-\frac{y}{3}-\frac{7}{8}$$

Multiply both sides by -8.

$$\frac{-\frac{1}{8}x}{-\frac{1}{8}}=\frac{-\frac{y}{3}-\frac{7}{8}}{-\frac{1}{8}}$$

Dividing by -\frac{1}{8} undoes the multiplication by -\frac{1}{8}.

$$x=\frac{-\frac{y}{3}-\frac{7}{8}}{-\frac{1}{8}}$$

Divide -\frac{y}{3}-\frac{7}{8} by -\frac{1}{8} by multiplying -\frac{y}{3}-\frac{7}{8} by the reciprocal of -\frac{1}{8}.

$$x=\frac{8y}{3}+7$$

Solve for y

$$y=\frac{3\left(x-7\right)}{8}$$

Steps for Solving Linear Equation

Subtract 0 from -3 to get -3.

$$\frac{y-0}{-3}=\frac{x-7}{-1-7}$$

Subtract 7 from -1 to get -8.

$$\frac{y-0}{-3}=\frac{x-7}{-8}$$

Multiply both numerator and denominator by -1.

$$\frac{y-0}{-3}=\frac{-x+7}{8}$$

Divide each term of y-0 by -3 to get -\frac{1}{3}y-0.

$$-\frac{1}{3}y-0=\frac{-x+7}{8}$$

Divide each term of -x+7 by 8 to get -\frac{1}{8}x+\frac{7}{8}.

$$-\frac{1}{3}y-0=-\frac{1}{8}x+\frac{7}{8}$$

Add 0 to both sides.

$$-\frac{1}{3}y=-\frac{1}{8}x+\frac{7}{8}+0$$

Add \frac{7}{8} and 0 to get \frac{7}{8}.

$$-\frac{1}{3}y=-\frac{1}{8}x+\frac{7}{8}$$

The equation is in standard form.

$$-\frac{1}{3}y=\frac{7-x}{8}$$

Multiply both sides by -3.

$$\frac{-\frac{1}{3}y}{-\frac{1}{3}}=\frac{7-x}{-\frac{1}{3}\times 8}$$

Dividing by -\frac{1}{3} undoes the multiplication by -\frac{1}{3}.

$$y=\frac{7-x}{-\frac{1}{3}\times 8}$$

Divide \frac{-x+7}{8} by -\frac{1}{3} by multiplying \frac{-x+7}{8} by the reciprocal of -\frac{1}{3}.

$$y=\frac{3x-21}{8}$$