Solve y/x-0.8=x-0.8/0.8

$$\frac { y } { x - 0.8 } = \frac { x - 0.8 } { 0.8 }$$

Solve for y

$$y=\frac{\left(5x-4\right)^{2}}{20}$$

$$x\neq \frac{4}{5}$$

Steps for Solving Linear Equation

Divide each term of x-0.8 by 0.8 to get \frac{x}{0.8}+\frac{-0.8}{0.8}.

$$\frac{y}{x-0.8}=\frac{x}{0.8}+\frac{-0.8}{0.8}$$

Divide -0.8 by 0.8 to get -1.

$$\frac{y}{x-0.8}=\frac{x}{0.8}-1$$

The equation is in standard form.

$$\frac{1}{x-0.8}y=\frac{5x}{4}-1$$

Divide both sides by \left(x-0.8\right)^{-1}.

$$\frac{\frac{1}{x-0.8}y\left(x-0.8\right)}{1}=\frac{\left(\frac{5x}{4}-1\right)\left(x-0.8\right)}{1}$$

Dividing by \left(x-0.8\right)^{-1} undoes the multiplication by \left(x-0.8\right)^{-1}.

$$y=\frac{\left(\frac{5x}{4}-1\right)\left(x-0.8\right)}{1}$$

Divide \frac{5x}{4}-1 by \left(x-0.8\right)^{-1}.

$$y=\frac{\left(x-0.8\right)\left(5x-4\right)}{4}$$

Solve for x (complex solution)

$$x=\frac{-2\sqrt{5y}+4}{5}$$

$$x=\frac{2\sqrt{5y}+4}{5}\text{, }y\neq 0$$

Solve for x

$$x=\frac{2\sqrt{5y}+4}{5}$$

$$x=\frac{-2\sqrt{5y}+4}{5}\text{, }y>0$$