Solve y/1-z=x+1

$$\frac { y } { 1 - z } = x + 1$$

Solve for x

$$x=\frac{1-z-y}{z-1}$$

$$z\neq 1$$

Steps for Solving Linear Equation

Multiply both sides of the equation by -z+1.

$$y=\left(-z+1\right)x-z+1$$

Use the distributive property to multiply -z+1 by x.

$$y=-zx+x-z+1$$

Swap sides so that all variable terms are on the left hand side.

$$-zx+x-z+1=y$$

Add z to both sides.

$$-zx+x+1=y+z$$

Subtract 1 from both sides.

$$-zx+x=y+z-1$$

Combine all terms containing x.

$$\left(-z+1\right)x=y+z-1$$

The equation is in standard form.

$$\left(1-z\right)x=y+z-1$$

Divide both sides by 1-z.

$$\frac{\left(1-z\right)x}{1-z}=\frac{y+z-1}{1-z}$$

Dividing by 1-z undoes the multiplication by 1-z.

$$x=\frac{y+z-1}{1-z}$$

Solve for y

$$y=-\left(z-1\right)\left(x+1\right)$$

$$z\neq 1$$

Solution Steps

Multiply both sides of the equation by -z+1.

$$y=\left(-z+1\right)x-z+1$$

Use the distributive property to multiply -z+1 by x.

$$y=-zx+x-z+1$$