Solve for x
x=\frac{y^{2}}{2\left(-\cos(y)+1\right)}
\nexists n_{1}\in \mathrm{Z}\text{ : }y=2\pi n_{1}
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2x=\frac{y^{2}}{1-\cos(y)}
Swap sides so that all variable terms are on the left hand side.
2x=\frac{y^{2}}{-\cos(y)+1}
The equation is in standard form.
\frac{2x}{2}=\frac{y^{2}}{2\left(-\cos(y)+1\right)}
Divide both sides by 2.
x=\frac{y^{2}}{2\left(-\cos(y)+1\right)}
Dividing by 2 undoes the multiplication by 2.
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