Solve for y
y=10
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\left(y+6\right)\left(y+5\right)=\left(y+2\right)\left(y+10\right)
Variable y cannot be equal to any of the values -6,-2 since division by zero is not defined. Multiply both sides of the equation by \left(y+2\right)\left(y+6\right), the least common multiple of y+2,y+6.
y^{2}+11y+30=\left(y+2\right)\left(y+10\right)
Use the distributive property to multiply y+6 by y+5 and combine like terms.
y^{2}+11y+30=y^{2}+12y+20
Use the distributive property to multiply y+2 by y+10 and combine like terms.
y^{2}+11y+30-y^{2}=12y+20
Subtract y^{2} from both sides.
11y+30=12y+20
Combine y^{2} and -y^{2} to get 0.
11y+30-12y=20
Subtract 12y from both sides.
-y+30=20
Combine 11y and -12y to get -y.
-y=20-30
Subtract 30 from both sides.
-y=-10
Subtract 30 from 20 to get -10.
y=10
Multiply both sides by -1.
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