Solve y+5/-7+5=x-4/5-4

$$\frac { y + 5 } { - 7 + 5 } = \frac { x - 4 } { 5 - 4 }$$

Solve for x

$$x=\frac{3-y}{2}$$

Solution Steps

Add -7 and 5 to get -2.

$$\frac{y+5}{-2}=\frac{x-4}{5-4}$$

Multiply both numerator and denominator by -1.

$$\frac{-y-5}{2}=\frac{x-4}{5-4}$$

Subtract 4 from 5 to get 1.

$$\frac{-y-5}{2}=\frac{x-4}{1}$$

Anything divided by one gives itself.

$$\frac{-y-5}{2}=x-4$$

Divide each term of -y-5 by 2 to get -\frac{1}{2}y-\frac{5}{2}.

$$-\frac{1}{2}y-\frac{5}{2}=x-4$$

Swap sides so that all variable terms are on the left hand side.

$$x-4=-\frac{1}{2}y-\frac{5}{2}$$

Add 4 to both sides.

$$x=-\frac{1}{2}y-\frac{5}{2}+4$$

Add -\frac{5}{2} and 4 to get \frac{3}{2}.

$$x=-\frac{1}{2}y+\frac{3}{2}$$

Solve for y

$$y=3-2x$$

Steps for Solving Linear Equation

Add -7 and 5 to get -2.

$$\frac{y+5}{-2}=\frac{x-4}{5-4}$$

Multiply both numerator and denominator by -1.

$$\frac{-y-5}{2}=\frac{x-4}{5-4}$$

Subtract 4 from 5 to get 1.

$$\frac{-y-5}{2}=\frac{x-4}{1}$$

Anything divided by one gives itself.

$$\frac{-y-5}{2}=x-4$$

Divide each term of -y-5 by 2 to get -\frac{1}{2}y-\frac{5}{2}.

$$-\frac{1}{2}y-\frac{5}{2}=x-4$$

Add \frac{5}{2} to both sides.

$$-\frac{1}{2}y=x-4+\frac{5}{2}$$

Add -4 and \frac{5}{2} to get -\frac{3}{2}.

$$-\frac{1}{2}y=x-\frac{3}{2}$$

Multiply both sides by -2.

$$\frac{-\frac{1}{2}y}{-\frac{1}{2}}=\frac{x-\frac{3}{2}}{-\frac{1}{2}}$$

Dividing by -\frac{1}{2} undoes the multiplication by -\frac{1}{2}.

$$y=\frac{x-\frac{3}{2}}{-\frac{1}{2}}$$

Divide x-\frac{3}{2} by -\frac{1}{2} by multiplying x-\frac{3}{2} by the reciprocal of -\frac{1}{2}.

$$y=3-2x$$