Solve x-4/3+3leqx/8

$$\frac { x - 4 } { 3 } + 3 \leq \frac { x } { 8 }$$

Solve for x

$$x\leq -8$$

Solution Steps

Multiply both sides of the equation by 24, the least common multiple of 3,8. Since 24 is positive, the inequality direction remains the same.

$$8\left(x-4\right)+72\leq 3x$$

Use the distributive property to multiply 8 by x-4.

$$8x-32+72\leq 3x$$

Add -32 and 72 to get 40.

$$8x+40\leq 3x$$

Subtract 3x from both sides.

$$8x+40-3x\leq 0$$

Combine 8x and -3x to get 5x.

$$5x+40\leq 0$$

Subtract 40 from both sides. Anything subtracted from zero gives its negation.

$$5x\leq -40$$

Divide both sides by 5. Since 5 is positive, the inequality direction remains the same.

$$x\leq \frac{-40}{5}$$

Divide -40 by 5 to get -8.

$$x\leq -8$$