Solve x-3/0-3+y+3/2+3=1

$$\frac { x - 3 } { 0 - 3 } + \frac { y + 3 } { 2 + 3 } = 1$$

Solve for x

$$x=\frac{3\left(y+3\right)}{5}$$

Steps for Solving Linear Equation

Subtract 3 from 0 to get -3.

$$\frac{x-3}{-3}+\frac{y+3}{2+3}=1$$

Multiply both numerator and denominator by -1.

$$\frac{-x+3}{3}+\frac{y+3}{2+3}=1$$

Add 2 and 3 to get 5.

$$\frac{-x+3}{3}+\frac{y+3}{5}=1$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 3 and 5 is 15. Multiply \frac{-x+3}{3} times \frac{5}{5}. Multiply \frac{y+3}{5} times \frac{3}{3}.

$$\frac{5\left(-x+3\right)}{15}+\frac{3\left(y+3\right)}{15}=1$$

Since \frac{5\left(-x+3\right)}{15} and \frac{3\left(y+3\right)}{15} have the same denominator, add them by adding their numerators.

$$\frac{5\left(-x+3\right)+3\left(y+3\right)}{15}=1$$

Do the multiplications in 5\left(-x+3\right)+3\left(y+3\right).

$$\frac{-5x+15+3y+9}{15}=1$$

Combine like terms in -5x+15+3y+9.

$$\frac{-5x+24+3y}{15}=1$$

Divide each term of -5x+24+3y by 15 to get -\frac{1}{3}x+\frac{8}{5}+\frac{1}{5}y.

$$-\frac{1}{3}x+\frac{8}{5}+\frac{1}{5}y=1$$

Subtract \frac{8}{5} from both sides.

$$-\frac{1}{3}x+\frac{1}{5}y=1-\frac{8}{5}$$

Subtract \frac{8}{5} from 1 to get -\frac{3}{5}.

$$-\frac{1}{3}x+\frac{1}{5}y=-\frac{3}{5}$$

Subtract \frac{1}{5}y from both sides.

$$-\frac{1}{3}x=-\frac{3}{5}-\frac{1}{5}y$$

The equation is in standard form.

$$-\frac{1}{3}x=\frac{-y-3}{5}$$

Multiply both sides by -3.

$$\frac{-\frac{1}{3}x}{-\frac{1}{3}}=\frac{-y-3}{-\frac{1}{3}\times 5}$$

Dividing by -\frac{1}{3} undoes the multiplication by -\frac{1}{3}.

$$x=\frac{-y-3}{-\frac{1}{3}\times 5}$$

Divide \frac{-3-y}{5} by -\frac{1}{3} by multiplying \frac{-3-y}{5} by the reciprocal of -\frac{1}{3}.

$$x=\frac{3y+9}{5}$$

Solve for y

$$y=\frac{5x}{3}-3$$

Steps for Solving Linear Equation

Subtract 3 from 0 to get -3.

$$\frac{x-3}{-3}+\frac{y+3}{2+3}=1$$

Multiply both numerator and denominator by -1.

$$\frac{-x+3}{3}+\frac{y+3}{2+3}=1$$

Add 2 and 3 to get 5.

$$\frac{-x+3}{3}+\frac{y+3}{5}=1$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 3 and 5 is 15. Multiply \frac{-x+3}{3} times \frac{5}{5}. Multiply \frac{y+3}{5} times \frac{3}{3}.

$$\frac{5\left(-x+3\right)}{15}+\frac{3\left(y+3\right)}{15}=1$$

Since \frac{5\left(-x+3\right)}{15} and \frac{3\left(y+3\right)}{15} have the same denominator, add them by adding their numerators.

$$\frac{5\left(-x+3\right)+3\left(y+3\right)}{15}=1$$

Do the multiplications in 5\left(-x+3\right)+3\left(y+3\right).

$$\frac{-5x+15+3y+9}{15}=1$$

Combine like terms in -5x+15+3y+9.

$$\frac{-5x+24+3y}{15}=1$$

Divide each term of -5x+24+3y by 15 to get -\frac{1}{3}x+\frac{8}{5}+\frac{1}{5}y.

$$-\frac{1}{3}x+\frac{8}{5}+\frac{1}{5}y=1$$

Add \frac{1}{3}x to both sides.

$$\frac{8}{5}+\frac{1}{5}y=1+\frac{1}{3}x$$

Subtract \frac{8}{5} from both sides.

$$\frac{1}{5}y=1+\frac{1}{3}x-\frac{8}{5}$$

Subtract \frac{8}{5} from 1 to get -\frac{3}{5}.

$$\frac{1}{5}y=-\frac{3}{5}+\frac{1}{3}x$$

The equation is in standard form.

$$\frac{1}{5}y=\frac{x}{3}-\frac{3}{5}$$

Multiply both sides by 5.

$$\frac{\frac{1}{5}y}{\frac{1}{5}}=\frac{\frac{x}{3}-\frac{3}{5}}{\frac{1}{5}}$$

Dividing by \frac{1}{5} undoes the multiplication by \frac{1}{5}.

$$y=\frac{\frac{x}{3}-\frac{3}{5}}{\frac{1}{5}}$$

Divide -\frac{3}{5}+\frac{x}{3} by \frac{1}{5} by multiplying -\frac{3}{5}+\frac{x}{3} by the reciprocal of \frac{1}{5}.

$$y=\frac{5x}{3}-3$$