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x+1>0 x+1<0
Denominator x+1 cannot be zero since division by zero is not defined. There are two cases.
x>-1
Consider the case when x+1 is positive. Move 1 to the right hand side.
x-1\geq x+1
The initial inequality does not change the direction when multiplied by x+1 for x+1>0.
x-x\geq 1+1
Move the terms containing x to the left hand side and all other terms to the right hand side.
0\geq 2
Combine like terms.
x\in \emptyset
Consider condition x>-1 specified above.
x<-1
Now consider the case when x+1 is negative. Move 1 to the right hand side.
x-1\leq x+1
The initial inequality changes the direction when multiplied by x+1 for x+1<0.
x-x\leq 1+1
Move the terms containing x to the left hand side and all other terms to the right hand side.
0\leq 2
Combine like terms.
x<-1
Consider condition x<-1 specified above.
x<-1
The final solution is the union of the obtained solutions.