Evaluate
\frac{1}{x+3}
Factor
\frac{1}{x+3}
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\frac{x+1}{x^{2}+4x+3}
Since \frac{x}{x^{2}+4x+3} and \frac{1}{x^{2}+4x+3} have the same denominator, add them by adding their numerators.
\frac{x+1}{\left(x+1\right)\left(x+3\right)}
Factor the expressions that are not already factored in \frac{x+1}{x^{2}+4x+3}.
\frac{1}{x+3}
Cancel out x+1 in both numerator and denominator.
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Limits
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