Solve for x
x\leq -\frac{20}{3}
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2x\geq 30+5\left(x-2\right)
Multiply both sides of the equation by 10, the least common multiple of 5,2. Since 10 is positive, the inequality direction remains the same.
2x\geq 30+5x-10
Use the distributive property to multiply 5 by x-2.
2x\geq 20+5x
Subtract 10 from 30 to get 20.
2x-5x\geq 20
Subtract 5x from both sides.
-3x\geq 20
Combine 2x and -5x to get -3x.
x\leq -\frac{20}{3}
Divide both sides by -3. Since -3 is negative, the inequality direction is changed.
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