Solve for x
x\geq \frac{120}{31}
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6x+10x\geq 120-15x
Multiply both sides of the equation by 30, the least common multiple of 5,3,2. Since 30 is positive, the inequality direction remains the same.
16x\geq 120-15x
Combine 6x and 10x to get 16x.
16x+15x\geq 120
Add 15x to both sides.
31x\geq 120
Combine 16x and 15x to get 31x.
x\geq \frac{120}{31}
Divide both sides by 31. Since 31 is positive, the inequality direction remains the same.
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