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5x+4\left(3x-2\right)\leq 20+10x
Multiply both sides of the equation by 20, the least common multiple of 4,5,2. Since 20 is positive, the inequality direction remains the same.
5x+12x-8\leq 20+10x
Use the distributive property to multiply 4 by 3x-2.
17x-8\leq 20+10x
Combine 5x and 12x to get 17x.
17x-8-10x\leq 20
Subtract 10x from both sides.
7x-8\leq 20
Combine 17x and -10x to get 7x.
7x\leq 20+8
Add 8 to both sides.
7x\leq 28
Add 20 and 8 to get 28.
x\leq \frac{28}{7}
Divide both sides by 7. Since 7 is positive, the inequality direction remains the same.
x\leq 4
Divide 28 by 7 to get 4.