Solve x/4^4-1/(-2)^6-(-1/16)^2

$$\frac { x } { 4 ^ { 4 } } - \frac { 1 } { ( - 2 ) ^ { 6 } } - ( - \frac { 1 } { 16 } ) ^ { 2 }$$

Evaluate

$$\frac{x-5}{256}$$

Short Solution Steps

Calculate 4 to the power of 4 and get 256.

$$\frac{x}{256}-\frac{1}{\left(-2\right)^{6}}-\left(-\frac{1}{16}\right)^{2}$$

Calculate -2 to the power of 6 and get 64.

$$\frac{x}{256}-\frac{1}{64}-\left(-\frac{1}{16}\right)^{2}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 256 and 64 is 256. Multiply \frac{1}{64} times \frac{4}{4}.

$$\frac{x}{256}-\frac{4}{256}-\left(-\frac{1}{16}\right)^{2}$$

Since \frac{x}{256} and \frac{4}{256} have the same denominator, subtract them by subtracting their numerators.

$$\frac{x-4}{256}-\left(-\frac{1}{16}\right)^{2}$$

Calculate -\frac{1}{16} to the power of 2 and get \frac{1}{256}.

$$\frac{x-4}{256}-\frac{1}{256}$$

Since \frac{x-4}{256} and \frac{1}{256} have the same denominator, subtract them by subtracting their numerators.

$$\frac{x-4-1}{256}$$

Combine like terms in x-4-1.

$$\frac{x-5}{256}$$

Factor

$$\frac{x-5}{256}$$