Solve x/4^4-1/(-2)^6=-(-1/16)

$$\frac { x } { 4 ^ { 4 } } - \frac { 1 } { ( - 2 ) ^ { 6 } } = - ( - \frac { 1 } { 16 } )$$

Solve for x

$$x=20$$

Steps for Solving Linear Equation

Calculate 4 to the power of 4 and get 256.

$$\frac{x}{256}-\frac{1}{\left(-2\right)^{6}}=-\left(-\frac{1}{16}\right)$$

Calculate -2 to the power of 6 and get 64.

$$\frac{x}{256}-\frac{1}{64}=-\left(-\frac{1}{16}\right)$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 256 and 64 is 256. Multiply \frac{1}{64} times \frac{4}{4}.

$$\frac{x}{256}-\frac{4}{256}=-\left(-\frac{1}{16}\right)$$

Since \frac{x}{256} and \frac{4}{256} have the same denominator, subtract them by subtracting their numerators.

$$\frac{x-4}{256}=-\left(-\frac{1}{16}\right)$$

The opposite of -\frac{1}{16} is \frac{1}{16}.

$$\frac{x-4}{256}=\frac{1}{16}$$

Divide each term of x-4 by 256 to get \frac{1}{256}x-\frac{1}{64}.

$$\frac{1}{256}x-\frac{1}{64}=\frac{1}{16}$$

Add \frac{1}{64} to both sides.

$$\frac{1}{256}x=\frac{1}{16}+\frac{1}{64}$$

Least common multiple of 16 and 64 is 64. Convert \frac{1}{16} and \frac{1}{64} to fractions with denominator 64.

$$\frac{1}{256}x=\frac{4}{64}+\frac{1}{64}$$

Since \frac{4}{64} and \frac{1}{64} have the same denominator, add them by adding their numerators.

$$\frac{1}{256}x=\frac{4+1}{64}$$

Add 4 and 1 to get 5.

$$\frac{1}{256}x=\frac{5}{64}$$

Multiply both sides by 256, the reciprocal of \frac{1}{256}.

$$x=\frac{5}{64}\times 256$$

Express \frac{5}{64}\times 256 as a single fraction.

$$x=\frac{5\times 256}{64}$$

Multiply 5 and 256 to get 1280.

$$x=\frac{1280}{64}$$

Divide 1280 by 64 to get 20.

$$x=20$$