Solve for x
x=\frac{9\left(y+12\right)}{4}
Solve for y
y=\frac{4\left(x-27\right)}{9}
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4x-3\times 3y=108
Multiply both sides of the equation by 12, the least common multiple of 3,4.
4x-9y=108
Multiply -3 and 3 to get -9.
4x=108+9y
Add 9y to both sides.
4x=9y+108
The equation is in standard form.
\frac{4x}{4}=\frac{9y+108}{4}
Divide both sides by 4.
x=\frac{9y+108}{4}
Dividing by 4 undoes the multiplication by 4.
x=\frac{9y}{4}+27
Divide 108+9y by 4.
4x-3\times 3y=108
Multiply both sides of the equation by 12, the least common multiple of 3,4.
4x-9y=108
Multiply -3 and 3 to get -9.
-9y=108-4x
Subtract 4x from both sides.
\frac{-9y}{-9}=\frac{108-4x}{-9}
Divide both sides by -9.
y=\frac{108-4x}{-9}
Dividing by -9 undoes the multiplication by -9.
y=\frac{4x}{9}-12
Divide 108-4x by -9.
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