Solve for x
x\geq 3
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x+3\leq 3x-3
Multiply both sides of the equation by 3. Since 3 is positive, the inequality direction remains the same.
x+3-3x\leq -3
Subtract 3x from both sides.
-2x+3\leq -3
Combine x and -3x to get -2x.
-2x\leq -3-3
Subtract 3 from both sides.
-2x\leq -6
Subtract 3 from -3 to get -6.
x\geq \frac{-6}{-2}
Divide both sides by -2. Since -2 is negative, the inequality direction is changed.
x\geq 3
Divide -6 by -2 to get 3.
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Limits
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