Solve for c
c=\frac{5\left(x-128\right)}{6}
Solve for x
x=\frac{6c}{5}+128
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x+6c=6x-640
Multiply both sides of the equation by 2.
6c=6x-640-x
Subtract x from both sides.
6c=5x-640
Combine 6x and -x to get 5x.
\frac{6c}{6}=\frac{5x-640}{6}
Divide both sides by 6.
c=\frac{5x-640}{6}
Dividing by 6 undoes the multiplication by 6.
c=\frac{5x}{6}-\frac{320}{3}
Divide -640+5x by 6.
x+6c=6x-640
Multiply both sides of the equation by 2.
x+6c-6x=-640
Subtract 6x from both sides.
-5x+6c=-640
Combine x and -6x to get -5x.
-5x=-640-6c
Subtract 6c from both sides.
-5x=-6c-640
The equation is in standard form.
\frac{-5x}{-5}=\frac{-6c-640}{-5}
Divide both sides by -5.
x=\frac{-6c-640}{-5}
Dividing by -5 undoes the multiplication by -5.
x=\frac{6c}{5}+128
Divide -640-6c by -5.
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Limits
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