Solve for x
x=\frac{2\left(y+12\right)}{3}
Solve for y
y=\frac{3\left(x-8\right)}{2}
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3x+2y=6x-24
Multiply both sides of the equation by 6, the least common multiple of 2,3.
3x+2y-6x=-24
Subtract 6x from both sides.
-3x+2y=-24
Combine 3x and -6x to get -3x.
-3x=-24-2y
Subtract 2y from both sides.
-3x=-2y-24
The equation is in standard form.
\frac{-3x}{-3}=\frac{-2y-24}{-3}
Divide both sides by -3.
x=\frac{-2y-24}{-3}
Dividing by -3 undoes the multiplication by -3.
x=\frac{2y}{3}+8
Divide -24-2y by -3.
3x+2y=6x-24
Multiply both sides of the equation by 6, the least common multiple of 2,3.
2y=6x-24-3x
Subtract 3x from both sides.
2y=3x-24
Combine 6x and -3x to get 3x.
\frac{2y}{2}=\frac{3x-24}{2}
Divide both sides by 2.
y=\frac{3x-24}{2}
Dividing by 2 undoes the multiplication by 2.
y=\frac{3x}{2}-12
Divide -24+3x by 2.
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