Solve for x
x=-\frac{10y}{3}+12
Solve for y
y=-\frac{3x}{10}+\frac{18}{5}
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3x+2\times 5y=36
Multiply both sides of the equation by 6, the least common multiple of 2,3.
3x+10y=36
Multiply 2 and 5 to get 10.
3x=36-10y
Subtract 10y from both sides.
\frac{3x}{3}=\frac{36-10y}{3}
Divide both sides by 3.
x=\frac{36-10y}{3}
Dividing by 3 undoes the multiplication by 3.
x=-\frac{10y}{3}+12
Divide 36-10y by 3.
3x+2\times 5y=36
Multiply both sides of the equation by 6, the least common multiple of 2,3.
3x+10y=36
Multiply 2 and 5 to get 10.
10y=36-3x
Subtract 3x from both sides.
\frac{10y}{10}=\frac{36-3x}{10}
Divide both sides by 10.
y=\frac{36-3x}{10}
Dividing by 10 undoes the multiplication by 10.
y=-\frac{3x}{10}+\frac{18}{5}
Divide 36-3x by 10.
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