Solve for x
x=\frac{12\left(y+7\right)}{7}
Solve for y
y=\frac{7\left(x-12\right)}{12}
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7x-12y=84
Multiply both sides of the equation by 84, the least common multiple of 12,7.
7x=84+12y
Add 12y to both sides.
7x=12y+84
The equation is in standard form.
\frac{7x}{7}=\frac{12y+84}{7}
Divide both sides by 7.
x=\frac{12y+84}{7}
Dividing by 7 undoes the multiplication by 7.
x=\frac{12y}{7}+12
Divide 84+12y by 7.
7x-12y=84
Multiply both sides of the equation by 84, the least common multiple of 12,7.
-12y=84-7x
Subtract 7x from both sides.
\frac{-12y}{-12}=\frac{84-7x}{-12}
Divide both sides by -12.
y=\frac{84-7x}{-12}
Dividing by -12 undoes the multiplication by -12.
y=\frac{7x}{12}-7
Divide 84-7x by -12.
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