Solve x/1+68/80-50/80=

$$\frac { x } { 1 } + \frac { 68 } { 80 } - \frac { 50 } { 80 } =$$

Evaluate

$$x = \frac{9}{40} = 0.225$$

Solution Steps

Anything divided by one gives itself.

$$x+\frac{68}{80}-\frac{50}{80}$$

Reduce the fraction \frac{68}{80} to lowest terms by extracting and canceling out 4.

$$x+\frac{17}{20}-\frac{50}{80}$$

Reduce the fraction \frac{50}{80} to lowest terms by extracting and canceling out 10.

$$x+\frac{17}{20}-\frac{5}{8}$$

Least common multiple of 20 and 8 is 40. Convert \frac{17}{20} and \frac{5}{8} to fractions with denominator 40.

$$x+\frac{34}{40}-\frac{25}{40}$$

Since \frac{34}{40} and \frac{25}{40} have the same denominator, subtract them by subtracting their numerators.

$$x+\frac{34-25}{40}$$

Subtract 25 from 34 to get 9.

$$x+\frac{9}{40}$$

Factor

$$\frac{40x+9}{40}$$

Solution Steps

Factor out \frac{1}{40}.

$$\frac{40x+9}{40}$$

Consider 40x+34-25. Multiply and combine like terms.

$$40x+9$$

Rewrite the complete factored expression.

$$\frac{40x+9}{40}$$