Solve x/sqrt{3}=1200-x

$$\frac { x } { \sqrt { 3 } } = 1200 - x$$

Solve for x

$$x=1800-600\sqrt{3}\approx 760.769515459$$

Steps for Solving Linear Equation

Rationalize the denominator of \frac{x}{\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.

$$\frac{x\sqrt{3}}{\left(\sqrt{3}\right)^{2}}=1200-x$$

The square of \sqrt{3} is 3.

$$\frac{x\sqrt{3}}{3}=1200-x$$

Add x to both sides.

$$\frac{x\sqrt{3}}{3}+x=1200$$

Multiply both sides of the equation by 3.

$$x\sqrt{3}+3x=3600$$

Combine all terms containing x.

$$\left(\sqrt{3}+3\right)x=3600$$

Divide both sides by \sqrt{3}+3.

$$\frac{\left(\sqrt{3}+3\right)x}{\sqrt{3}+3}=\frac{3600}{\sqrt{3}+3}$$

Dividing by \sqrt{3}+3 undoes the multiplication by \sqrt{3}+3.

$$x=\frac{3600}{\sqrt{3}+3}$$

Divide 3600 by \sqrt{3}+3.

$$x=1800-600\sqrt{3}$$