Solve x/sin15^circ=frac{16/sqrt{2}}{frac{sqrt{2}}{2}}

$$\frac { x } { \sin 15 ^ { \circ } } = \frac { \frac { 16 } { \sqrt { 2 } } } { \frac { \sqrt { 2 } } { 2 } }$$

Solve for x

$$x=4.14110472164033184$$

Steps for Solving Linear Equation

Evaluate trigonometric functions in the problem

$$\frac{x}{0.25881904510252074} = \frac{\frac{16}{\sqrt{2}}}{\frac{\sqrt{2}}{2}}$$

Divide \frac{16}{\sqrt{2}} by \frac{\sqrt{2}}{2} by multiplying \frac{16}{\sqrt{2}} by the reciprocal of \frac{\sqrt{2}}{2}.

$$\frac{x}{0.25881904510252074}=\frac{16\times 2}{\sqrt{2}\sqrt{2}}$$

Multiply 16 and 2 to get 32.

$$\frac{x}{0.25881904510252074}=\frac{32}{\sqrt{2}\sqrt{2}}$$

Multiply \sqrt{2} and \sqrt{2} to get 2.

$$\frac{x}{0.25881904510252074}=\frac{32}{2}$$

Divide 32 by 2 to get 16.

$$\frac{x}{0.25881904510252074}=16$$

Multiply both sides by 0.25881904510252074.

$$x=16\times 0.25881904510252074$$

Multiply 16 and 0.25881904510252074 to get 4.14110472164033184.

$$x=4.14110472164033184$$