Solve x^3/3+3+6x+20x-5

$$\frac { x ^ { 3 } } { 3 } + 3 + 6 x + 20 x - 5$$

Evaluate

$$\frac{x^{3}}{3}+26x-2$$

Short Solution Steps

Combine 6x and 20x to get 26x.

$$\frac{x^{3}}{3}+3+26x-5$$

Subtract 5 from 3 to get -2.

$$\frac{x^{3}}{3}-2+26x$$

To add or subtract expressions, expand them to make their denominators the same. Multiply -2+26x times \frac{3}{3}.

$$\frac{x^{3}}{3}+\frac{3\left(-2+26x\right)}{3}$$

Since \frac{x^{3}}{3} and \frac{3\left(-2+26x\right)}{3} have the same denominator, add them by adding their numerators.

$$\frac{x^{3}+3\left(-2+26x\right)}{3}$$

Do the multiplications in x^{3}+3\left(-2+26x\right).

$$\frac{x^{3}-6+78x}{3}$$

Factor

$$\frac{x^{3}+78x-6}{3}$$

Solution Steps

Factor out \frac{1}{3}. Polynomial x^{3}+78x-6 is not factored since it does not have any rational roots.

$$\frac{x^{3}-6+78x}{3}$$