Solve x^2-4x/2x^frac{1{2}}=

$$\frac { x ^ { 2 } - 4 x } { 2 x ^ { \frac { 1 } { 2 } } } =$$

Factor

$$\frac{\sqrt{x}\left(x-4\right)}{2}$$

Solution Steps

Factor the expressions that are not already factored in \frac{x^{2}-4x}{2x^{\frac{1}{2}}}.

$$factor(\frac{x\left(x-4\right)}{2\sqrt{x}})$$

Cancel out \sqrt{x} in both numerator and denominator.

$$factor(\frac{\sqrt{x}\left(x-4\right)}{2})$$

Use the distributive property to multiply \sqrt{x} by x-4.

$$factor(\frac{\sqrt{x}x-4\sqrt{x}}{2})$$

Consider \sqrt{x}x-4\sqrt{x}. Factor out \sqrt{x}.

$$\sqrt{x}\left(x-4\right)$$

Rewrite the complete factored expression.

$$\frac{\left(x-4\right)\sqrt{x}}{2}$$

Evaluate

$$\frac{\sqrt{x}\left(x-4\right)}{2}$$