Solve x^2-36/3x-18*9x+18/x^2+8x+12

$$\frac { x ^ { 2 } - 36 } { 3 x - 18 } \cdot \frac { 9 x + 18 } { x ^ { 2 } + 8 x + 12 }$$

Evaluate

$$3$$

Short Solution Steps

Factor the expressions that are not already factored in \frac{x^{2}-36}{3x-18}.

$$\frac{\left(x-6\right)\left(x+6\right)}{3\left(x-6\right)}\times \frac{9x+18}{x^{2}+8x+12}$$

Cancel out x-6 in both numerator and denominator.

$$\frac{x+6}{3}\times \frac{9x+18}{x^{2}+8x+12}$$

Factor the expressions that are not already factored in \frac{9x+18}{x^{2}+8x+12}.

$$\frac{x+6}{3}\times \frac{9\left(x+2\right)}{\left(x+2\right)\left(x+6\right)}$$

Cancel out x+2 in both numerator and denominator.

$$\frac{x+6}{3}\times \frac{9}{x+6}$$

Multiply \frac{x+6}{3} times \frac{9}{x+6} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\left(x+6\right)\times 9}{3\left(x+6\right)}$$

Cancel out 3\left(x+6\right) in both numerator and denominator.

$$3$$

Factor

$$3$$