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x^{2}-27x=3\times 4
Multiply both sides by 4.
x^{2}-27x=12
Multiply 3 and 4 to get 12.
x^{2}-27x-12=0
Subtract 12 from both sides.
x=\frac{-\left(-27\right)±\sqrt{\left(-27\right)^{2}-4\left(-12\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -27 for b, and -12 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-27\right)±\sqrt{729-4\left(-12\right)}}{2}
Square -27.
x=\frac{-\left(-27\right)±\sqrt{729+48}}{2}
Multiply -4 times -12.
x=\frac{-\left(-27\right)±\sqrt{777}}{2}
Add 729 to 48.
x=\frac{27±\sqrt{777}}{2}
The opposite of -27 is 27.
x=\frac{\sqrt{777}+27}{2}
Now solve the equation x=\frac{27±\sqrt{777}}{2} when ± is plus. Add 27 to \sqrt{777}.
x=\frac{27-\sqrt{777}}{2}
Now solve the equation x=\frac{27±\sqrt{777}}{2} when ± is minus. Subtract \sqrt{777} from 27.
x=\frac{\sqrt{777}+27}{2} x=\frac{27-\sqrt{777}}{2}
The equation is now solved.
x^{2}-27x=3\times 4
Multiply both sides by 4.
x^{2}-27x=12
Multiply 3 and 4 to get 12.
x^{2}-27x+\left(-\frac{27}{2}\right)^{2}=12+\left(-\frac{27}{2}\right)^{2}
Divide -27, the coefficient of the x term, by 2 to get -\frac{27}{2}. Then add the square of -\frac{27}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-27x+\frac{729}{4}=12+\frac{729}{4}
Square -\frac{27}{2} by squaring both the numerator and the denominator of the fraction.
x^{2}-27x+\frac{729}{4}=\frac{777}{4}
Add 12 to \frac{729}{4}.
\left(x-\frac{27}{2}\right)^{2}=\frac{777}{4}
Factor x^{2}-27x+\frac{729}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-\frac{27}{2}\right)^{2}}=\sqrt{\frac{777}{4}}
Take the square root of both sides of the equation.
x-\frac{27}{2}=\frac{\sqrt{777}}{2} x-\frac{27}{2}=-\frac{\sqrt{777}}{2}
Simplify.
x=\frac{\sqrt{777}+27}{2} x=\frac{27-\sqrt{777}}{2}
Add \frac{27}{2} to both sides of the equation.