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\frac{\left(x^{2}-1\right)\left(4x+4x^{2}+4x^{3}\right)}{\left(1-x^{3}\right)\left(4x^{2}+4x\right)}
Divide \frac{x^{2}-1}{1-x^{3}} by \frac{4x^{2}+4x}{4x+4x^{2}+4x^{3}} by multiplying \frac{x^{2}-1}{1-x^{3}} by the reciprocal of \frac{4x^{2}+4x}{4x+4x^{2}+4x^{3}}.
\frac{4x\left(x-1\right)\left(x+1\right)\left(x^{2}+x+1\right)}{4x\left(x-1\right)\left(x+1\right)\left(-x^{2}-x-1\right)}
Factor the expressions that are not already factored.
\frac{-4x\left(x-1\right)\left(x+1\right)\left(-x^{2}-x-1\right)}{4x\left(x-1\right)\left(x+1\right)\left(-x^{2}-x-1\right)}
Extract the negative sign in 1+x+x^{2}.
-1
Cancel out 4x\left(x-1\right)\left(x+1\right)\left(-x^{2}-x-1\right) in both numerator and denominator.