Solve x^2-1/frac{10x{x+1}}

$$\frac { x ^ { 2 } - 1 } { \frac { 10 x } { x + 1 } }$$

Evaluate

$$\frac{\left(x-1\right)\left(x+1\right)^{2}}{10x}$$

Short Solution Steps

Divide x^{2}-1 by \frac{10x}{x+1} by multiplying x^{2}-1 by the reciprocal of \frac{10x}{x+1}.

$$\frac{\left(x^{2}-1\right)\left(x+1\right)}{10x}$$

Use the distributive property to multiply x^{2}-1 by x+1.

$$\frac{x^{3}+x^{2}-x-1}{10x}$$

Expand

$$\frac{x^{2}}{10}+\frac{x}{10}-\frac{1}{10}-\frac{1}{10x}$$

Short Solution Steps

Divide x^{2}-1 by \frac{10x}{x+1} by multiplying x^{2}-1 by the reciprocal of \frac{10x}{x+1}.

$$\frac{\left(x^{2}-1\right)\left(x+1\right)}{10x}$$

Use the distributive property to multiply x^{2}-1 by x+1.

$$\frac{x^{3}+x^{2}-x-1}{10x}$$