Evaluate
\frac{x}{x+8}
Factor
\frac{x}{x+8}
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\frac{x^{2}-8x}{x^{2}-64}
Since \frac{x^{2}}{x^{2}-64} and \frac{8x}{x^{2}-64} have the same denominator, subtract them by subtracting their numerators.
\frac{x\left(x-8\right)}{\left(x-8\right)\left(x+8\right)}
Factor the expressions that are not already factored in \frac{x^{2}-8x}{x^{2}-64}.
\frac{x}{x+8}
Cancel out x-8 in both numerator and denominator.
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