Solve x^2/4-2x+4

$$\frac { x ^ { 2 } } { 4 } - 2 x + 4$$

Evaluate

$$\frac{\left(x-4\right)^{2}}{4}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply -2x+4 times \frac{4}{4}.

$$\frac{x^{2}}{4}+\frac{4\left(-2x+4\right)}{4}$$

Since \frac{x^{2}}{4} and \frac{4\left(-2x+4\right)}{4} have the same denominator, add them by adding their numerators.

$$\frac{x^{2}+4\left(-2x+4\right)}{4}$$

Do the multiplications in x^{2}+4\left(-2x+4\right).

$$\frac{x^{2}-8x+16}{4}$$

Factor

$$\frac{\left(x-4\right)^{2}}{4}$$

Solution Steps

Factor out \frac{1}{4}.

$$\frac{x^{2}-8x+16}{4}$$

Consider x^{2}-8x+16. Use the perfect square formula, a^{2}-2ab+b^{2}=\left(a-b\right)^{2}, where a=x and b=4.

$$\left(x-4\right)^{2}$$

Rewrite the complete factored expression.

$$\frac{\left(x-4\right)^{2}}{4}$$