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9x^{2}=4x^{2}+20
Multiply both sides of the equation by 36, the least common multiple of 4,9.
9x^{2}-4x^{2}=20
Subtract 4x^{2} from both sides.
5x^{2}=20
Combine 9x^{2} and -4x^{2} to get 5x^{2}.
5x^{2}-20=0
Subtract 20 from both sides.
x^{2}-4=0
Divide both sides by 5.
\left(x-2\right)\left(x+2\right)=0
Consider x^{2}-4. Rewrite x^{2}-4 as x^{2}-2^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
x=2 x=-2
To find equation solutions, solve x-2=0 and x+2=0.
9x^{2}=4x^{2}+20
Multiply both sides of the equation by 36, the least common multiple of 4,9.
9x^{2}-4x^{2}=20
Subtract 4x^{2} from both sides.
5x^{2}=20
Combine 9x^{2} and -4x^{2} to get 5x^{2}.
x^{2}=\frac{20}{5}
Divide both sides by 5.
x^{2}=4
Divide 20 by 5 to get 4.
x=2 x=-2
Take the square root of both sides of the equation.
9x^{2}=4x^{2}+20
Multiply both sides of the equation by 36, the least common multiple of 4,9.
9x^{2}-4x^{2}=20
Subtract 4x^{2} from both sides.
5x^{2}=20
Combine 9x^{2} and -4x^{2} to get 5x^{2}.
5x^{2}-20=0
Subtract 20 from both sides.
x=\frac{0±\sqrt{0^{2}-4\times 5\left(-20\right)}}{2\times 5}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 5 for a, 0 for b, and -20 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 5\left(-20\right)}}{2\times 5}
Square 0.
x=\frac{0±\sqrt{-20\left(-20\right)}}{2\times 5}
Multiply -4 times 5.
x=\frac{0±\sqrt{400}}{2\times 5}
Multiply -20 times -20.
x=\frac{0±20}{2\times 5}
Take the square root of 400.
x=\frac{0±20}{10}
Multiply 2 times 5.
x=2
Now solve the equation x=\frac{0±20}{10} when ± is plus. Divide 20 by 10.
x=-2
Now solve the equation x=\frac{0±20}{10} when ± is minus. Divide -20 by 10.
x=2 x=-2
The equation is now solved.