Solve x^2/1+x-x^2+x^3

$$\frac { x ^ { 2 } } { 1 + x } - x ^ { 2 } + x ^ { 3 }$$

Evaluate

$$\frac{x^{4}}{x+1}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply -x^{2}+x^{3} times \frac{1+x}{1+x}.

$$\frac{x^{2}}{1+x}+\frac{\left(-x^{2}+x^{3}\right)\left(1+x\right)}{1+x}$$

Since \frac{x^{2}}{1+x} and \frac{\left(-x^{2}+x^{3}\right)\left(1+x\right)}{1+x} have the same denominator, add them by adding their numerators.

$$\frac{x^{2}+\left(-x^{2}+x^{3}\right)\left(1+x\right)}{1+x}$$

Do the multiplications in x^{2}+\left(-x^{2}+x^{3}\right)\left(1+x\right).

$$\frac{x^{2}-x^{2}-x^{3}+x^{3}+x^{4}}{1+x}$$

Combine like terms in x^{2}-x^{2}-x^{3}+x^{3}+x^{4}.

$$\frac{x^{4}}{1+x}$$

Factor

$$\frac{x^{4}}{x+1}$$