Solve x^2+2/3-x^2+1/4=x+5/12

$$\frac { x ^ { 2 } + 2 } { 3 } - \frac { x ^ { 2 } + 1 } { 4 } = \frac { x + 5 } { 12 }$$

Solve for x

$$x=1$$

$$x=0$$

Steps Using Factoring

Multiply both sides of the equation by 12, the least common multiple of 3,4,12.

$$4\left(x^{2}+2\right)-3\left(x^{2}+1\right)=x+5$$

Use the distributive property to multiply 4 by x^{2}+2.

$$4x^{2}+8-3\left(x^{2}+1\right)=x+5$$

Use the distributive property to multiply -3 by x^{2}+1.

$$4x^{2}+8-3x^{2}-3=x+5$$

Combine 4x^{2} and -3x^{2} to get x^{2}.

$$x^{2}+8-3=x+5$$

Subtract 3 from 8 to get 5.

$$x^{2}+5=x+5$$

Subtract x from both sides.

$$x^{2}+5-x=5$$

Subtract 5 from both sides.

$$x^{2}+5-x-5=0$$

Subtract 5 from 5 to get 0.

$$x^{2}-x=0$$

Factor out x.

$$x\left(x-1\right)=0$$

To find equation solutions, solve x=0 and x-1=0.

$$x=0 x=1$$

Steps Using the Quadratic Formula

Multiply both sides of the equation by 12, the least common multiple of 3,4,12.

$$4\left(x^{2}+2\right)-3\left(x^{2}+1\right)=x+5$$

Use the distributive property to multiply 4 by x^{2}+2.

$$4x^{2}+8-3\left(x^{2}+1\right)=x+5$$

Use the distributive property to multiply -3 by x^{2}+1.

$$4x^{2}+8-3x^{2}-3=x+5$$

Combine 4x^{2} and -3x^{2} to get x^{2}.

$$x^{2}+8-3=x+5$$

Subtract 3 from 8 to get 5.

$$x^{2}+5=x+5$$

Subtract x from both sides.

$$x^{2}+5-x=5$$

Subtract 5 from both sides.

$$x^{2}+5-x-5=0$$

Subtract 5 from 5 to get 0.

$$x^{2}-x=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -1 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-1\right)±\sqrt{1}}{2}$$

Take the square root of 1.

$$x=\frac{-\left(-1\right)±1}{2}$$

The opposite of -1 is 1.

$$x=\frac{1±1}{2}$$

Now solve the equation x=\frac{1±1}{2} when ± is plus. Add 1 to 1.

$$x=\frac{2}{2}$$

Divide 2 by 2.

$$x=1$$

Now solve the equation x=\frac{1±1}{2} when ± is minus. Subtract 1 from 1.

$$x=\frac{0}{2}$$

Divide 0 by 2.

$$x=0$$

The equation is now solved.

$$x=1 x=0$$

Steps for Completing the Square

Multiply both sides of the equation by 12, the least common multiple of 3,4,12.

$$4\left(x^{2}+2\right)-3\left(x^{2}+1\right)=x+5$$

Use the distributive property to multiply 4 by x^{2}+2.

$$4x^{2}+8-3\left(x^{2}+1\right)=x+5$$

Use the distributive property to multiply -3 by x^{2}+1.

$$4x^{2}+8-3x^{2}-3=x+5$$

Combine 4x^{2} and -3x^{2} to get x^{2}.

$$x^{2}+8-3=x+5$$

Subtract 3 from 8 to get 5.

$$x^{2}+5=x+5$$

Subtract x from both sides.

$$x^{2}+5-x=5$$

Subtract 5 from both sides.

$$x^{2}+5-x-5=0$$

Subtract 5 from 5 to get 0.

$$x^{2}-x=0$$

Divide -1, the coefficient of the x term, by 2 to get -\frac{1}{2}. Then add the square of -\frac{1}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}-x+\left(-\frac{1}{2}\right)^{2}=\left(-\frac{1}{2}\right)^{2}$$

Square -\frac{1}{2} by squaring both the numerator and the denominator of the fraction.

$$x^{2}-x+\frac{1}{4}=\frac{1}{4}$$

Factor x^{2}-x+\frac{1}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-\frac{1}{2}\right)^{2}=\frac{1}{4}$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x-\frac{1}{2}\right)^{2}}=\sqrt{\frac{1}{4}}$$

Simplify.

$$x-\frac{1}{2}=\frac{1}{2} x-\frac{1}{2}=-\frac{1}{2}$$

Add \frac{1}{2} to both sides of the equation.

$$x=1 x=0$$