Evaluate
\frac{x+8}{x-8}
Expand
\frac{x+8}{x-8}
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\frac{\left(x^{2}+11x+24\right)\left(x-1\right)}{\left(x^{2}+2x-3\right)\left(x-8\right)}
Divide \frac{x^{2}+11x+24}{x^{2}+2x-3} by \frac{x-8}{x-1} by multiplying \frac{x^{2}+11x+24}{x^{2}+2x-3} by the reciprocal of \frac{x-8}{x-1}.
\frac{\left(x-1\right)\left(x+3\right)\left(x+8\right)}{\left(x-8\right)\left(x-1\right)\left(x+3\right)}
Factor the expressions that are not already factored.
\frac{x+8}{x-8}
Cancel out \left(x-1\right)\left(x+3\right) in both numerator and denominator.
\frac{\left(x^{2}+11x+24\right)\left(x-1\right)}{\left(x^{2}+2x-3\right)\left(x-8\right)}
Divide \frac{x^{2}+11x+24}{x^{2}+2x-3} by \frac{x-8}{x-1} by multiplying \frac{x^{2}+11x+24}{x^{2}+2x-3} by the reciprocal of \frac{x-8}{x-1}.
\frac{\left(x-1\right)\left(x+3\right)\left(x+8\right)}{\left(x-8\right)\left(x-1\right)\left(x+3\right)}
Factor the expressions that are not already factored.
\frac{x+8}{x-8}
Cancel out \left(x-1\right)\left(x+3\right) in both numerator and denominator.
Examples
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Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
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