Solve x+p/4=q

$$\frac { x + p } { 4 } = q$$

Solve for p

$$p=-\left(x-4q\right)$$

Steps for Solving Linear Equation

Divide each term of x+p by 4 to get \frac{1}{4}x+\frac{1}{4}p.

$$\frac{1}{4}x+\frac{1}{4}p=q$$

Subtract \frac{1}{4}x from both sides.

$$\frac{1}{4}p=q-\frac{1}{4}x$$

The equation is in standard form.

$$\frac{1}{4}p=-\frac{x}{4}+q$$

Multiply both sides by 4.

$$\frac{\frac{1}{4}p}{\frac{1}{4}}=\frac{-\frac{x}{4}+q}{\frac{1}{4}}$$

Dividing by \frac{1}{4} undoes the multiplication by \frac{1}{4}.

$$p=\frac{-\frac{x}{4}+q}{\frac{1}{4}}$$

Divide q-\frac{x}{4} by \frac{1}{4} by multiplying q-\frac{x}{4} by the reciprocal of \frac{1}{4}.

$$p=4q-x$$

Solve for q

$$q=\frac{x+p}{4}$$

Solution Steps

Divide each term of x+p by 4 to get \frac{1}{4}x+\frac{1}{4}p.

$$\frac{1}{4}x+\frac{1}{4}p=q$$

Swap sides so that all variable terms are on the left hand side.

$$q=\frac{1}{4}x+\frac{1}{4}p$$