Solve x+8/6x+60divx^2-64/x^2+2x-80

$$\frac { x + 8 } { 6 x + 60 } \div \frac { x ^ { 2 } - 64 } { x ^ { 2 } + 2 x - 80 }$$

Evaluate

$$\frac{1}{6}\approx 0.166666667$$

Short Solution Steps

Divide \frac{x+8}{6x+60} by \frac{x^{2}-64}{x^{2}+2x-80} by multiplying \frac{x+8}{6x+60} by the reciprocal of \frac{x^{2}-64}{x^{2}+2x-80}.

$$\frac{\left(x+8\right)\left(x^{2}+2x-80\right)}{\left(6x+60\right)\left(x^{2}-64\right)}$$

Factor the expressions that are not already factored.

$$\frac{\left(x-8\right)\left(x+8\right)\left(x+10\right)}{6\left(x-8\right)\left(x+8\right)\left(x+10\right)}$$

Cancel out \left(x-8\right)\left(x+8\right)\left(x+10\right) in both numerator and denominator.

$$\frac{1}{6}$$

Factor

$$\frac{1}{2 \cdot 3} = 0.16666666666666666$$