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\left(x+5\right)\left(x+5\right)+x\times 5x=6x\left(x+5\right)
Variable x cannot be equal to any of the values -5,0 since division by zero is not defined. Multiply both sides of the equation by x\left(x+5\right), the least common multiple of x,x+5.
\left(x+5\right)^{2}+x\times 5x=6x\left(x+5\right)
Multiply x+5 and x+5 to get \left(x+5\right)^{2}.
x^{2}+10x+25+x\times 5x=6x\left(x+5\right)
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+5\right)^{2}.
x^{2}+10x+25+x^{2}\times 5=6x\left(x+5\right)
Multiply x and x to get x^{2}.
6x^{2}+10x+25=6x\left(x+5\right)
Combine x^{2} and x^{2}\times 5 to get 6x^{2}.
6x^{2}+10x+25=6x^{2}+30x
Use the distributive property to multiply 6x by x+5.
6x^{2}+10x+25-6x^{2}=30x
Subtract 6x^{2} from both sides.
10x+25=30x
Combine 6x^{2} and -6x^{2} to get 0.
10x+25-30x=0
Subtract 30x from both sides.
-20x+25=0
Combine 10x and -30x to get -20x.
-20x=-25
Subtract 25 from both sides. Anything subtracted from zero gives its negation.
x=\frac{-25}{-20}
Divide both sides by -20.
x=\frac{5}{4}
Reduce the fraction \frac{-25}{-20} to lowest terms by extracting and canceling out -5.