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Solve for r
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r\left(x+4\right)=x\times \frac{1}{1}
Variable r cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by rx, the least common multiple of x,r.
rx+4r=x\times \frac{1}{1}
Use the distributive property to multiply r by x+4.
rx+4r=x\times 1
Anything divided by one gives itself.
rx+4r=x
Reorder the terms.
\left(x+4\right)r=x
Combine all terms containing r.
\frac{\left(x+4\right)r}{x+4}=\frac{x}{x+4}
Divide both sides by x+4.
r=\frac{x}{x+4}
Dividing by x+4 undoes the multiplication by x+4.
r=\frac{x}{x+4}\text{, }r\neq 0
Variable r cannot be equal to 0.
r\left(x+4\right)=x\times \frac{1}{1}
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by rx, the least common multiple of x,r.
rx+4r=x\times \frac{1}{1}
Use the distributive property to multiply r by x+4.
rx+4r=x\times 1
Anything divided by one gives itself.
rx+4r-x\times 1=0
Subtract x\times 1 from both sides.
rx+4r-x=0
Reorder the terms.
rx-x=-4r
Subtract 4r from both sides. Anything subtracted from zero gives its negation.
\left(r-1\right)x=-4r
Combine all terms containing x.
\frac{\left(r-1\right)x}{r-1}=-\frac{4r}{r-1}
Divide both sides by r-1.
x=-\frac{4r}{r-1}
Dividing by r-1 undoes the multiplication by r-1.
x=-\frac{4r}{r-1}\text{, }x\neq 0
Variable x cannot be equal to 0.