Solve for x
x=-5
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\left(x+4\right)\left(x+3\right)=\left(x+7\right)\left(x+6\right)
Variable x cannot be equal to any of the values -7,-4 since division by zero is not defined. Multiply both sides of the equation by \left(x+4\right)\left(x+7\right), the least common multiple of x+7,x+4.
x^{2}+7x+12=\left(x+7\right)\left(x+6\right)
Use the distributive property to multiply x+4 by x+3 and combine like terms.
x^{2}+7x+12=x^{2}+13x+42
Use the distributive property to multiply x+7 by x+6 and combine like terms.
x^{2}+7x+12-x^{2}=13x+42
Subtract x^{2} from both sides.
7x+12=13x+42
Combine x^{2} and -x^{2} to get 0.
7x+12-13x=42
Subtract 13x from both sides.
-6x+12=42
Combine 7x and -13x to get -6x.
-6x=42-12
Subtract 12 from both sides.
-6x=30
Subtract 12 from 42 to get 30.
x=\frac{30}{-6}
Divide both sides by -6.
x=-5
Divide 30 by -6 to get -5.
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Limits
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