Solve x+3/7>x-5quad7x

$$\frac { x + 3 } { 7 } > x - 5 \quad 7 x$$

Solve for x

$$x>-\frac{3}{239}$$

Solution Steps

Multiply both sides of the equation by 7. Since 7 is positive, the inequality direction remains the same.

$$x+3>7x-35\times 7x$$

Multiply 35 and 7 to get 245.

$$x+3>7x-245x$$

Combine 7x and -245x to get -238x.

$$x+3>-238x$$

Add 238x to both sides.

$$x+3+238x>0$$

Combine x and 238x to get 239x.

$$239x+3>0$$

Subtract 3 from both sides. Anything subtracted from zero gives its negation.

$$239x>-3$$

Divide both sides by 239. Since 239 is positive, the inequality direction remains the same.

$$x>-\frac{3}{239}$$