Solve x+3/7>x-5=

$$\frac { x + 3 } { 7 } > x - 5 =$$

Solve for x

$$x<\frac{19}{3}$$

Solution Steps

Multiply both sides of the equation by 7. Since 7 is positive, the inequality direction remains the same.

$$x+3>7x-35$$

Subtract 7x from both sides.

$$x+3-7x>-35$$

Combine x and -7x to get -6x.

$$-6x+3>-35$$

Subtract 3 from both sides.

$$-6x>-35-3$$

Subtract 3 from -35 to get -38.

$$-6x>-38$$

Divide both sides by -6. Since -6 is negative, the inequality direction is changed.

$$x<\frac{-38}{-6}$$

Reduce the fraction \frac{-38}{-6} to lowest terms by extracting and canceling out -2.

$$x<\frac{19}{3}$$