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\left(x+2\right)\left(x+2\right)=\left(x-2\right)\left(x+5\right)
Variable x cannot be equal to any of the values -2,2 since division by zero is not defined. Multiply both sides of the equation by \left(x-2\right)\left(x+2\right), the least common multiple of x-2,x+2.
\left(x+2\right)^{2}=\left(x-2\right)\left(x+5\right)
Multiply x+2 and x+2 to get \left(x+2\right)^{2}.
x^{2}+4x+4=\left(x-2\right)\left(x+5\right)
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+2\right)^{2}.
x^{2}+4x+4=x^{2}+3x-10
Use the distributive property to multiply x-2 by x+5 and combine like terms.
x^{2}+4x+4-x^{2}=3x-10
Subtract x^{2} from both sides.
4x+4=3x-10
Combine x^{2} and -x^{2} to get 0.
4x+4-3x=-10
Subtract 3x from both sides.
x+4=-10
Combine 4x and -3x to get x.
x=-10-4
Subtract 4 from both sides.
x=-14
Subtract 4 from -10 to get -14.