Solve for x
x=-14
Graph
Share
Copied to clipboard
\left(x+2\right)\left(x+2\right)=\left(x-2\right)\left(x+5\right)
Variable x cannot be equal to any of the values -2,2 since division by zero is not defined. Multiply both sides of the equation by \left(x-2\right)\left(x+2\right), the least common multiple of x-2,x+2.
\left(x+2\right)^{2}=\left(x-2\right)\left(x+5\right)
Multiply x+2 and x+2 to get \left(x+2\right)^{2}.
x^{2}+4x+4=\left(x-2\right)\left(x+5\right)
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+2\right)^{2}.
x^{2}+4x+4=x^{2}+3x-10
Use the distributive property to multiply x-2 by x+5 and combine like terms.
x^{2}+4x+4-x^{2}=3x-10
Subtract x^{2} from both sides.
4x+4=3x-10
Combine x^{2} and -x^{2} to get 0.
4x+4-3x=-10
Subtract 3x from both sides.
x+4=-10
Combine 4x and -3x to get x.
x=-10-4
Subtract 4 from both sides.
x=-14
Subtract 4 from -10 to get -14.
Examples
Quadratic equation
{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}