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\left(8x+40\right)\left(x+2\right)-\left(8x+8\right)x=\left(x+1\right)\left(x+5\right)
Variable x cannot be equal to any of the values -5,-1 since division by zero is not defined. Multiply both sides of the equation by 8\left(x+1\right)\left(x+5\right), the least common multiple of x+1,x+5,8.
8x^{2}+56x+80-\left(8x+8\right)x=\left(x+1\right)\left(x+5\right)
Use the distributive property to multiply 8x+40 by x+2 and combine like terms.
8x^{2}+56x+80-\left(8x^{2}+8x\right)=\left(x+1\right)\left(x+5\right)
Use the distributive property to multiply 8x+8 by x.
8x^{2}+56x+80-8x^{2}-8x=\left(x+1\right)\left(x+5\right)
To find the opposite of 8x^{2}+8x, find the opposite of each term.
56x+80-8x=\left(x+1\right)\left(x+5\right)
Combine 8x^{2} and -8x^{2} to get 0.
48x+80=\left(x+1\right)\left(x+5\right)
Combine 56x and -8x to get 48x.
48x+80=x^{2}+6x+5
Use the distributive property to multiply x+1 by x+5 and combine like terms.
48x+80-x^{2}=6x+5
Subtract x^{2} from both sides.
48x+80-x^{2}-6x=5
Subtract 6x from both sides.
42x+80-x^{2}=5
Combine 48x and -6x to get 42x.
42x+80-x^{2}-5=0
Subtract 5 from both sides.
42x+75-x^{2}=0
Subtract 5 from 80 to get 75.
-x^{2}+42x+75=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-42±\sqrt{42^{2}-4\left(-1\right)\times 75}}{2\left(-1\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -1 for a, 42 for b, and 75 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-42±\sqrt{1764-4\left(-1\right)\times 75}}{2\left(-1\right)}
Square 42.
x=\frac{-42±\sqrt{1764+4\times 75}}{2\left(-1\right)}
Multiply -4 times -1.
x=\frac{-42±\sqrt{1764+300}}{2\left(-1\right)}
Multiply 4 times 75.
x=\frac{-42±\sqrt{2064}}{2\left(-1\right)}
Add 1764 to 300.
x=\frac{-42±4\sqrt{129}}{2\left(-1\right)}
Take the square root of 2064.
x=\frac{-42±4\sqrt{129}}{-2}
Multiply 2 times -1.
x=\frac{4\sqrt{129}-42}{-2}
Now solve the equation x=\frac{-42±4\sqrt{129}}{-2} when ± is plus. Add -42 to 4\sqrt{129}.
x=21-2\sqrt{129}
Divide -42+4\sqrt{129} by -2.
x=\frac{-4\sqrt{129}-42}{-2}
Now solve the equation x=\frac{-42±4\sqrt{129}}{-2} when ± is minus. Subtract 4\sqrt{129} from -42.
x=2\sqrt{129}+21
Divide -42-4\sqrt{129} by -2.
x=21-2\sqrt{129} x=2\sqrt{129}+21
The equation is now solved.
\left(8x+40\right)\left(x+2\right)-\left(8x+8\right)x=\left(x+1\right)\left(x+5\right)
Variable x cannot be equal to any of the values -5,-1 since division by zero is not defined. Multiply both sides of the equation by 8\left(x+1\right)\left(x+5\right), the least common multiple of x+1,x+5,8.
8x^{2}+56x+80-\left(8x+8\right)x=\left(x+1\right)\left(x+5\right)
Use the distributive property to multiply 8x+40 by x+2 and combine like terms.
8x^{2}+56x+80-\left(8x^{2}+8x\right)=\left(x+1\right)\left(x+5\right)
Use the distributive property to multiply 8x+8 by x.
8x^{2}+56x+80-8x^{2}-8x=\left(x+1\right)\left(x+5\right)
To find the opposite of 8x^{2}+8x, find the opposite of each term.
56x+80-8x=\left(x+1\right)\left(x+5\right)
Combine 8x^{2} and -8x^{2} to get 0.
48x+80=\left(x+1\right)\left(x+5\right)
Combine 56x and -8x to get 48x.
48x+80=x^{2}+6x+5
Use the distributive property to multiply x+1 by x+5 and combine like terms.
48x+80-x^{2}=6x+5
Subtract x^{2} from both sides.
48x+80-x^{2}-6x=5
Subtract 6x from both sides.
42x+80-x^{2}=5
Combine 48x and -6x to get 42x.
42x-x^{2}=5-80
Subtract 80 from both sides.
42x-x^{2}=-75
Subtract 80 from 5 to get -75.
-x^{2}+42x=-75
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
\frac{-x^{2}+42x}{-1}=-\frac{75}{-1}
Divide both sides by -1.
x^{2}+\frac{42}{-1}x=-\frac{75}{-1}
Dividing by -1 undoes the multiplication by -1.
x^{2}-42x=-\frac{75}{-1}
Divide 42 by -1.
x^{2}-42x=75
Divide -75 by -1.
x^{2}-42x+\left(-21\right)^{2}=75+\left(-21\right)^{2}
Divide -42, the coefficient of the x term, by 2 to get -21. Then add the square of -21 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-42x+441=75+441
Square -21.
x^{2}-42x+441=516
Add 75 to 441.
\left(x-21\right)^{2}=516
Factor x^{2}-42x+441. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-21\right)^{2}}=\sqrt{516}
Take the square root of both sides of the equation.
x-21=2\sqrt{129} x-21=-2\sqrt{129}
Simplify.
x=2\sqrt{129}+21 x=21-2\sqrt{129}
Add 21 to both sides of the equation.